((3x^2)+10x-32)=0

Solution for ((3x^2)+10x-32)=0 equation:

((3x^2)+10x-32)=0

We get rid of parentheses

3x^2+10x-32=0

a = 3; b = 10; c = -32;
Δ = b2-4ac
Δ = 102-4·3·(-32)
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-22}{2*3}=\frac{-32}{6}
=-5+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+22}{2*3}=\frac{12}{6}
=2
$